-16k^2+8k+24=20

Solution for -16k^2+8k+24=20 equation:

-16k^2+8k+24=20

We move all terms to the left:

-16k^2+8k+24-(20)=0

We add all the numbers together, and all the variables

-16k^2+8k+4=0

a = -16; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·(-16)·4
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{5}}{2*-16}=\frac{-8-8\sqrt{5}}{-32}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{5}}{2*-16}=\frac{-8+8\sqrt{5}}{-32}
$